# Public Solving: Calculating the wind chill

Chris Bongers
·Dec 28, 2021·

Santa's sled is pretty modern. Hey, we even upgraded it to have an autopilot. But now, the elves want to surprise Santa by adding a wind chill gauge.

The wind chill is the "feel" temperature, you know when it's like 30 degrees, but it feels like 35?

You can find the complete puzzle here.

To do this, we can use an already provided mathematical calculation which can be found here.

The wind chill can be calculated for English and Metric values.

The main thing we have to achieve today is to actually make the formula in JavaScript. This should be a pretty straightforward process.

The formula for English units looks like this:

``````35.74 + 0.6215T – 35.75 (V^0.16) + 0.4275T (V^0.16)
``````

Where `T` = Temperature in degrees Fahrenheit and `V` = wind speed in miles per hour.

In JavaScript this should look similar to this:

``````35.74 + 0.6215 * temperature - 35.75 * windSpeed ** 0.16 + 0.4275 * temperature * windSpeed ** 0.16
``````

Did you note the `(V^0.16)` exponent? We can use `Math.pow` or the shortcut `**` for that.

Then we can simply wrap this in a `Math.round` to get the rounded number.

``````return Math.round(
35.74 +
0.6215 * temperature -
35.75 * windSpeed ** 0.16 +
0.4275 * temperature * windSpeed ** 0.16
);
``````

However, we also need a way to calculate the metric version.

I decided to just catch and return the English units beforehand.

And if that didn't hit, surely it must be the metric version.

``````if (units === 'US') {
return Math.round(
35.74 +
0.6215 * temperature -
35.75 * windSpeed ** 0.16 +
0.4275 * temperature * windSpeed ** 0.16
);
}

return Math.round(
13.12 +
0.6215 * temperature -
11.37 * windSpeed ** 0.16 +
0.3965 * temperature * windSpeed ** 0.16
);
``````

And that's it! We solved the issue.

Let's try it out and see if our test turns green.

Would love to hear what you would do differently to solve this problem.